已知【3x+2y+1]+2(x-y-1)^2=0,则x=？，y=？

|3x+2y+1|+2(x-y-1)^2=0
第一个是不是绝对值？？？否则没办法做！！！
因为绝对值大于等于0
完全平方大于等于0
所以，|3x+2y+1|=(x-y-1)^2=0
3x+2y+1=0...(1)
x-y-1=0...2x-2y-2=0...(2)
(1)+(2)
5x-1=0,x=1/5
1/5-y-1=0,-y=1-1/5=4/5,y=-4/5

答案，x=1/5
y=-4/5